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Home > NCERT Solutions Class 6 Mathematics > Chapter 2 - Whole Numbers > Exercise 2.3 > Question 6

NCERT Solutions Class 6 Mathematics Solutions for Exercise 2.3 in Chapter 2 - Whole Numbers

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Q4) Find using distributive property :

(a) 728 × 101

(b) 5437 × 1001

(c) 824 × 25

(d) 4275 × 125

(e) 504 × 35

Answer:

Solution 4:

(a)

728× 101

=729× (100+1)

=728× 100 + 728× 1

=72800 + 728

=73528

(b)

5437 × 1001

=5437 × (1000+1)

= 5437× 1000 + 5437× 1

=5437000 + 5437

=5442437

(c)

824× 25

= 824 × (20+5)

= 824× 20 + 824 × 5

=16480+4120

=20600

(d) 4275× 125

=4275× (100+20+5)

=4275× 100 + 4275× 20 +4275× 5

=427500 + 85500 + 21375

= 534375

(e) 504 × 35

= 35× (500+4)

= 35× 500 + 35× 4

=17500 + 140

=17640

Verified answer

Distributive property is a×(b+c)=a×b+a×c

Associative property is a×b±a×c=a×(b±c)

using this in given examples.

(i)

−39×99

=−39×[100−1]

=−39×100−(−39)×1⋯⋯[distributive property]

=−3900+39=−3861

(ii)

(−85)×43+43×(−15)

=43×(−85)+43×(−15)⋯[∵a×b=b×a]

=43×[−85−15]⋯⋯[associative property]

=43×(−100)=−4300

(iii)

53×(−9)−(−109)×53

53×(−9)−53×(−109)⋯[∵a×b=b×a]

=53×[(−9)−(−109)]⋯⋯[associative property]

=53×[−9+109]=53×100=5300

(iv)

68×(−17)+(−68)×3

=68×(−17)−68×3

=68×[(−17)−3]⋯⋯[associative property]

=68×(−20)

=−1360

kamikaze

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