Answer:

Step-by-step explanation:

Answer:

To solve this problem, let's break it down step by step. Let's assume Ranjana bought x 10-rupee cards, y 5-rupee cards, and z 15-rupee cards.

According to the given information, we can set up the following equations:

10x + 5y + 15z = 245 (the total cost of the cards is ₹245)

y = (2/3)x (2/3 as many 5-rupee cards as 10-rupee cards)

z = (1/5)x (1/5 as many 15-rupee cards as 10-rupee cards)

Now, we can substitute the values of y and z into the first equation to solve for x:

10x + 5((2/3)x) + 15((1/5)x) = 245

Simplifying the equation, we get:

10x + (10/3)x + (3/5)x = 245

Combining like terms, we have:

(59/15)x = 245

Multiplying both sides by 15/59, we find:

x = 245 × (15/59)

Calculating the value of x, we get:

x ≈ 62.84

Since we can't have a fraction of a card, we can round x to the nearest whole number:

x ≈ 63

Now that we know the value of x, we can substitute it back into the equations for y and z to find their values:

y = (2/3) × 63 ≈ 42

z = (1/5) × 63 ≈ 12.6

Again, rounding to the nearest whole number, we have:

y ≈ 42

z ≈ 13

So, Ranjana bought approximately 63 10-rupee cards, 42 5-rupee cards, and 13 15-rupee cards.