A bag contains 15 balls of three different colour green,black,and yellow A ball is drawn at random from the bag the probability of green ball is 1/3.. the probability of of yellow ball is 1/5 (a) what is the probability of black ball? (b) how many balls are green?
Answers & Comments
answer of b is 5
Answer:
(a) probability of black ball =![\dfrac{7}{15} \dfrac{7}{15}](https://tex.z-dn.net/?f=%5Cdfrac%7B7%7D%7B15%7D)
(b) number of green balls = 5
Step-by-step explanation:
Total number of ball = 15
probability of green ball =![\dfrac{1}{3} \dfrac{1}{3}](https://tex.z-dn.net/?f=%5Cdfrac%7B1%7D%7B3%7D)
hence, the number of green ball = total number of ball x probability of green ball
= 5
probability of yellow ball =![\dfrac{1}{5} \dfrac{1}{5}](https://tex.z-dn.net/?f=%5Cdfrac%7B1%7D%7B5%7D)
so, the number of yellow ball = total number of ball x probability of yellow ball
= 3
So, the number of black ball = total number of ball - number of green ball - number of yellow ball
= 15 - 5 - 3
= 7
Hence, the probability of getting black ball =![\dfrac{number\ of\ black\ ball}{total\ number\ of\ ball} \dfrac{number\ of\ black\ ball}{total\ number\ of\ ball}](https://tex.z-dn.net/?f=%5Cdfrac%7Bnumber%5C%20of%5C%20black%5C%20ball%7D%7Btotal%5C%20number%5C%20of%5C%20ball%7D)
Hence, the probability black ball is
and total number of green ball is 5.