5. A flashlight that is powered by 3 Volts and uses a bulb with a resistance of
60 Ω will have a current of ________ Amps.
60 Ω will have a current of ________ Amps.
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My answer is 0.05amps.
Given: V=3volts
R=60ohms
Solution: I=V/R
=3volts/60ohms
=0.05Amps.
Therefore, A flashlight that is powered by 3 Volts and uses a bulb with a resistance of 60 Ω will have a current of 0.05 Amps.
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