5.) A 50g traveler's bag is being pulled by along the floor by a tourist with a force of 50N. Neglecting friction, what the acceleration of the bag? How much force is exerted by the floor on the bag if the friction is neglected? (12pts)
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FORCE
To find the acceleration of the bag, we can use Newton's second law of motion, which states that the acceleration of an object is directly proportional to the net force applied to it and inversely proportional to its mass. Mathematically, this can be expressed as:
F = m * a
Where F is the net force, m is the mass, and a is the acceleration.
Given:
Mass of the bag (m) = 50 g = 0.05 kg
Force applied by the tourist (F) = 50 N
Using the equation F = m * a, we can rearrange it to solve for acceleration (a):
a = F / m
Plugging in the values, we get:
a = 50 N / 0.05 kg
a = 1000 m/s²
Therefore, the acceleration of the bag is 1000 m/s².
Since friction is neglected, the force exerted by the floor on the bag is equal to the force applied by the tourist, which is 50 N.