[tex]The \: Weight \: of \: Book \: A \\ \\ = 650[/tex]
[tex]The \: Weight \: of \: Book \: B \\ \\ = 400[/tex]
[tex] = 4 \: of \:book \: A + 5 \: copies \: of \: \\ book \: B \\ \\ = (4 \times 650) + (5 \times 400) \\ \\ = 2600 + 2400 \\ \\ = 5000 \: gm \\ \\ = 5 \: kg[/tex]
[tex] = x \: copies \: of \: book \: A + y \: \\ copy \: of \: book \: B \\ \\ = (x \times 650 \: g) + (y \times 400 \: g) \\ \\ = 650x + 400y[/tex]
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Answers & Comments
Given :
[tex] = 3°+ \frac{4°}{5°} \\ [/tex]
To do :
[tex]Find \: the \: value [/tex]
Solution Explanation :
[tex]= 3°+ \frac{4°}{5°} \\ \\ = 1 + \frac{1}{1} \\ \\ = 1 + 1 \\ \\ = 2[/tex]
[tex]The \: Weight \: of \: Book \: A \\ \\ = 650[/tex]
[tex]The \: Weight \: of \: Book \: B \\ \\ = 400[/tex]
[tex] = 4 \: of \:book \: A + 5 \: copies \: of \: \\ book \: B \\ \\ = (4 \times 650) + (5 \times 400) \\ \\ = 2600 + 2400 \\ \\ = 5000 \: gm \\ \\ = 5 \: kg[/tex]
[tex] = x \: copies \: of \: book \: A + y \: \\ copy \: of \: book \: B \\ \\ = (x \times 650 \: g) + (y \times 400 \: g) \\ \\ = 650x + 400y[/tex]