Verified answer

Given :-

[tex]\Large\dashrightarrow\mathsf{6x = \frac{6}{4x} }[/tex]

Solution :-

[tex]\begin{gathered}\Large\dashrightarrow\mathsf{6x = \frac{6}{4x} }\\\end{gathered} \mathsf {\: \: \: , \: \: x \: \cancel{ = } \: 0}[/tex]

[tex]\begin{gathered}\Large\dashrightarrow\mathsf{6x = \frac{3}{2x} }\\\end{gathered}[/tex]

[tex]\begin{gathered}\Large\dashrightarrow\mathsf{12x {}^{2} = 3 }\\\end{gathered}[/tex]

[tex]\begin{gathered}\Large\dashrightarrow\mathsf{ {x}^{2} = \frac{1}{4} }\\\end{gathered}[/tex]

[tex]\begin{gathered}\Large\dashrightarrow\mathsf{x = \pm \: \frac{1}{2} }\\\end{gathered}[/tex]

[tex] \boxed{\begin{gathered}\Large\dashrightarrow\mathsf{x = \frac{1}{2} }\\\end{gathered} \: \: \: \mathsf{ and} \: \: \: \: \: \begin{gathered}\Large\mathsf{ \frac{x}{2} = \frac{1}{2} }\\\end{gathered}} \: \: \prime \: \boxed{\mathsf{\: x \: \neq \: 0}}\begin{gathered}\Large\mathsf{}\\\end{gathered}[/tex]

[tex]\begin{gathered}\Large\dashrightarrow\mathsf \red{x _{1} = - \frac{1}{2} }\end{gathered}[/tex]

[tex]\begin{gathered}\Large\dashrightarrow\mathsf \red{x _{2} = \frac{1}{2} }\\\end{gathered}[/tex]

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