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rat111
@rat111
August 2021
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4x^2 +4bx-(a^2-b^2)
please help me
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Collosus
The answer is in the picture I am sending.
Plz mark as brainliest
2 votes
Thanks 7
rat111
thanks
rat111
will surely mark as brainliest
Collosus
plz mark as brainliest
Collosus
thank you
GauravGumber
4x² +4bx -(a²- b²)
x=[ -4b ± √[16b² + 4*4*(a² - b²)] ] ÷ 2*4
x= [ -4b ± √ 16b² +16a² - 16b² ] ÷ 8
x = [ -4b ± √16a² ] ÷ 8
x= [ -4b ± 4a ] ÷ 8
x= [ -b ± a ] ÷ 2
x= (-b-a) / 2 OR x = (-b + a) / 2
2x+a+b=0 OR ( 2x + b-a )=0
So ,,4x² +4bx -(a²- b²) = (2x + a + b) ( 2x + b - a )
2 votes
Thanks 4
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Answers & Comments
Plz mark as brainliest
x=[ -4b ± √[16b² + 4*4*(a² - b²)] ] ÷ 2*4
x= [ -4b ± √ 16b² +16a² - 16b² ] ÷ 8
x = [ -4b ± √16a² ] ÷ 8
x= [ -4b ± 4a ] ÷ 8
x= [ -b ± a ] ÷ 2
x= (-b-a) / 2 OR x = (-b + a) / 2
2x+a+b=0 OR ( 2x + b-a )=0
So ,,4x² +4bx -(a²- b²) = (2x + a + b) ( 2x + b - a )