1.) Firstly, remember what the equation of a line is: (for the equation of a line that is in slope-intercept structure), where is the slope, and is the y-intercept.
2.) To start, you understand what is; it's solely the slope, which you said was . So you can immediately fill in the condition for a line fairly to get: .
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3.) Next, what about , the y-intercept? To find , think about your point means: . When of the line is , of the line must be . Since you said, the line passes through this point .
4.) Presently, have a look at our line's equation up until now. The value for is the thing that we need. The has kept now set, and and are only two "free variables" staying there. We can plug anything we need in for and here. However, we need the condition for the line that explicitly goes through the point .
5.) So, how about plugging in for the number and for the number ? That will permit us to determine the value for for the specific line that goes through the point you gave.
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⇒ Solving for b:
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6.a.) Lastly, plug in or substitute the value of and back into the slope-intercept equation.
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⇒ (Slope-Intercept Form)
6.b.) Unless you want the equation of the line in standard form, you may transpose the value of and the variable to the opposite sides of the equation.
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⇒ (Standard Form)
I hope this helps you understand this concept in Mathematics.
Answers & Comments
Answer:
Step-by-step explanation:
1.) Firstly, remember what the equation of a line is:
(for the equation of a line that is in slope-intercept structure), where
is the slope, and
is the y-intercept.
2.) To start, you understand what
is; it's solely the slope, which you said was
. So you can immediately fill in the condition for a line fairly to get:
.
⇒![m = \frac{1}{4} m = \frac{1}{4}](https://tex.z-dn.net/?f=m%20%3D%20%5Cfrac%7B1%7D%7B4%7D)
⇒
⇒ ![y= (\frac{1}{4})x + b y= (\frac{1}{4})x + b](https://tex.z-dn.net/?f=y%3D%20%28%5Cfrac%7B1%7D%7B4%7D%29x%20%2B%20b)
3.) Next, what about
, the y-intercept? To find
, think about your
point means:
. When
of the line is
,
of the line must be
. Since you said, the line passes through this point
.
4.) Presently, have a look at our line's equation up until now. The value for
is the thing that we need. The
has kept now set, and
and
are only two "free variables" staying there. We can plug anything we need in for
and
here. However, we need the condition for the line that explicitly goes through the point
.
5.) So, how about plugging in for
the number
and for
the number
? That will permit us to determine the value for
for the specific line that goes through the point you gave.
⇒![(x, y) = (-4, 3) (x, y) = (-4, 3)](https://tex.z-dn.net/?f=%28x%2C%20y%29%20%3D%20%28-4%2C%203%29)
⇒
⇒![3 = (\frac{1}{4})(-4) + b 3 = (\frac{1}{4})(-4) + b](https://tex.z-dn.net/?f=3%20%3D%20%28%5Cfrac%7B1%7D%7B4%7D%29%28-4%29%20%2B%20b)
⇒ Solving for b:![3 = \frac{1 \times -4}{4} + b 3 = \frac{1 \times -4}{4} + b](https://tex.z-dn.net/?f=3%20%3D%20%5Cfrac%7B1%20%5Ctimes%20-4%7D%7B4%7D%20%2B%20b)
⇒![3 = \frac{1 \times -4}{4} + b 3 = \frac{1 \times -4}{4} + b](https://tex.z-dn.net/?f=3%20%3D%20%5Cfrac%7B1%20%5Ctimes%20-4%7D%7B4%7D%20%2B%20b)
⇒![3 = -1 + b 3 = -1 + b](https://tex.z-dn.net/?f=3%20%3D%20-1%20%2B%20b)
⇒
⇒![b = 4 b = 4](https://tex.z-dn.net/?f=b%20%3D%204)
6.a.) Lastly, plug in or substitute the value of
and
back into the slope-intercept equation.
⇒![y = mx + b y = mx + b](https://tex.z-dn.net/?f=y%20%3D%20mx%20%2B%20b)
⇒![y = (\frac{1}{4})x + (4) y = (\frac{1}{4})x + (4)](https://tex.z-dn.net/?f=y%20%3D%20%28%5Cfrac%7B1%7D%7B4%7D%29x%20%2B%20%284%29)
⇒
(Slope-Intercept Form)
6.b.) Unless you want the equation of the line in standard form, you may transpose the value of
and the variable
to the opposite sides of the equation.
⇒![y = \frac{1}{4}x + 4 y = \frac{1}{4}x + 4](https://tex.z-dn.net/?f=y%20%3D%20%5Cfrac%7B1%7D%7B4%7Dx%20%2B%204)
⇒![y - (y) - (4) = \frac{1}{4}x + 4 - (y) - (4) y - (y) - (4) = \frac{1}{4}x + 4 - (y) - (4)](https://tex.z-dn.net/?f=y%20-%20%28y%29%20-%20%284%29%20%3D%20%5Cfrac%7B1%7D%7B4%7Dx%20%2B%204%20-%20%28y%29%20-%20%284%29)
⇒![-4 = \frac{1}{4}x - y -4 = \frac{1}{4}x - y](https://tex.z-dn.net/?f=-4%20%3D%20%5Cfrac%7B1%7D%7B4%7Dx%20-%20y)
⇒
(Standard Form)
I hope this helps you understand this concept in Mathematics.
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