Answer:
mark the brainliest if correct
Step-by-step explanation:
cos A = B/H = 3/4
so we get B=3 and H=4
using Pythagoras theorem
p²= 16-9
p= √7
sinA = P/H = √7/4
The value of 32sin(
2
A
)sin(
5A
)
=16(cos2A−cos3A)
=16(2cos
A−1−4cos
3
A+3cosA)
=16(2×
16
9
−1−4×
64
27
+3×
4
=18−16+27+36=11
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Answers & Comments
Answer:
mark the brainliest if correct
Step-by-step explanation:
cos A = B/H = 3/4
so we get B=3 and H=4
using Pythagoras theorem
p²= 16-9
p= √7
sinA = P/H = √7/4
Answer:
The value of 32sin(
2
A
)sin(
2
5A
)
=16(cos2A−cos3A)
=16(2cos
2
A−1−4cos
3
A+3cosA)
=16(2×
16
9
−1−4×
64
27
+3×
4
3
)
=18−16+27+36=11