Answer:
According to the Quadratic Formula, m , the solution for Am^2+Bm+C = 0 , where A, B and C are numbers, often called coefficients, is given by :
- B ± √ B2-4AC
m = ————————
2A
In our case, A = 4
B = 1
C = -3
Accordingly, B2 - 4AC =
1 - (-48) =
49
Applying the quadratic formula :
-1 ± √ 49
m = —————
8
Can √ 49 be simplified ?
Yes! The prime factorization of 49 is
7•7
To be able to remove something from under the radical, there have to be 2 instances of it (because we are taking a square i.e. second root).
√ 49 = √ 7•7 =
± 7 • √ 1 =
± 7
So now we are looking at:
m = ( -1 ± 7) / 8
Two real solutions:
m =(-1+√49)/8=(-1+7)/8= 0.750
or:
m =(-1-√49)/8=(-1-7)/8= -1.000
ANSWERS :
Two solutions were found :
m = -1
m = 3/4 = 0.750
Let me know if you understand
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Answers & Comments
Answer:
According to the Quadratic Formula, m , the solution for Am^2+Bm+C = 0 , where A, B and C are numbers, often called coefficients, is given by :
- B ± √ B2-4AC
m = ————————
2A
In our case, A = 4
B = 1
C = -3
Accordingly, B2 - 4AC =
1 - (-48) =
49
Applying the quadratic formula :
-1 ± √ 49
m = —————
8
Can √ 49 be simplified ?
Yes! The prime factorization of 49 is
7•7
To be able to remove something from under the radical, there have to be 2 instances of it (because we are taking a square i.e. second root).
√ 49 = √ 7•7 =
± 7 • √ 1 =
± 7
So now we are looking at:
m = ( -1 ± 7) / 8
Two real solutions:
m =(-1+√49)/8=(-1+7)/8= 0.750
or:
m =(-1-√49)/8=(-1-7)/8= -1.000
ANSWERS :
Two solutions were found :
m = -1
m = 3/4 = 0.750
Let me know if you understand