Answer:
[tex]255 < > { {nhvgjncfhh \: h \: log( \gamma e \cos( \cot(?) ) ) }^{?} }^{?} \times \frac{?}{?} \times \frac{?}{?} [/tex]
Step-by-step explanation:
Consider the equation,
tanθ=
4
3
Now,
tan
2
θ=
16
9
1+tan
θ=1+
=
25
sec
secθ=±
5
cosθ=±
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Verified answer
Answer:
[tex]255 < > { {nhvgjncfhh \: h \: log( \gamma e \cos( \cot(?) ) ) }^{?} }^{?} \times \frac{?}{?} \times \frac{?}{?} [/tex]
Step-by-step explanation:
Consider the equation,
tanθ=
4
3
Now,
tan
2
θ=
16
9
1+tan
2
θ=1+
16
9
=
16
25
sec
2
θ=
16
25
secθ=±
4
5
cosθ=±
5
4