Answer:
y= 1(x-3)^2 - 4
Step-by-step explanation:
The standard form of a quadratic equation is
y = ax^2 + bx + c
If you multiply the binomials (x-5)(x-1) using FOIL rules, you should get
y = x^2 - 6x + 5. This is the standard form.
The vertex form of a quadratic equation can be written as
y= a(x-h)^2 + k
h is the axis of symmetry and can be calculated by -b/2a
and we get h=-(-6)/2*1 = 3 (remember that we know a=1 and b=-6)
And k represents the value of the function when x=h
so plug in 3 for x and find the value of the function
y = x^2 - 6x + 5
= 3^2 - 6*3 + 5
= -4 (this is k)
now we know h and k, so the vertex form can be written as
x²-4x-5
x² - 5x + x - 5
x² - 4x-5
Hope it helpssss
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Answers & Comments
Answer:
y= 1(x-3)^2 - 4
Step-by-step explanation:
The standard form of a quadratic equation is
y = ax^2 + bx + c
If you multiply the binomials (x-5)(x-1) using FOIL rules, you should get
y = x^2 - 6x + 5. This is the standard form.
The vertex form of a quadratic equation can be written as
y= a(x-h)^2 + k
h is the axis of symmetry and can be calculated by -b/2a
and we get h=-(-6)/2*1 = 3 (remember that we know a=1 and b=-6)
And k represents the value of the function when x=h
so plug in 3 for x and find the value of the function
y = x^2 - 6x + 5
= 3^2 - 6*3 + 5
= -4 (this is k)
now we know h and k, so the vertex form can be written as
y= 1(x-3)^2 - 4
Answer:
x²-4x-5
Step-by-step explanation:
x² - 5x + x - 5
x² - 4x-5
Hope it helpssss