Give the sum of the following arithmetic sequences.
1.) -12- 7 - 2 + 3 + ... + 488
6. the integers from - 10 to 21
2.) 56 +47 + 38 + 29 + ...- 124
7. the even integers from -18 to 52
3.) - 4 - 11 - 18 - ... - 102
8. the multiples of 3 from 12 to 6,048
4.) -1.2 +0.3 + 1.8 + ... + 12.
9. the terms less than 22, a1= -2, d = 3
5.) - 1/4+1/4+3/4+...+3 3/4)
10. the terms greater than -107, a1 = -8, d = -9
Answers & Comments
Step-by-step explanation:
1.) Distribute all the given:
D= 5 an= 488
n=? a1= -12
First, wee need to find the value of "n"
Substitute to the formula: an=a1 +(n-1)d
488= -12+(n-1)5
488+12=5n
500=5n
n= 100
Now, we find the value of "n" so that we can now find the sum.
Finding the sum: S=n/2 (a1+an)
S= 100/2 (-12+488)
S= 50(476)
S= 23,800
If we add -12 -7 -2+3+...+488 the result will be "23,800"
"Analyze the given question and also follow the formula"