Answer:
Step-by-step explanation:
Let's denote the quantity of water to be added as x
the milk contains= 10%water
total quantity of milk= 40 litres
the quantity of water in the initial milk is 10 of 40 litres=0.1×40=4 litres.
After adding x litres of water
the total quantity of the mixture becomes 40+x litres.
The new mixture is intended to contain 20% water. So, the quantity of water in the new mixture should be 20% of (40+x) litres
Now, we can set up an equation:
4+x=0.2×(40+x)
Let's solve for x:
4+x=8+0.2x
Subtract 0.2x from both sides:
0.8x=4
Divide by 0.8:
x=5
Therefore, 5 litres of water need to be added to the 40 litres of milk to achieve a mixture containing 20% water.
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Answers & Comments
Answer:
Step-by-step explanation:
Let's denote the quantity of water to be added as x
the milk contains= 10%water
total quantity of milk= 40 litres
the quantity of water in the initial milk is 10 of 40 litres=0.1×40=4 litres.
After adding x litres of water
the total quantity of the mixture becomes 40+x litres.
The new mixture is intended to contain 20% water. So, the quantity of water in the new mixture should be 20% of (40+x) litres
Now, we can set up an equation:
4+x=0.2×(40+x)
Let's solve for x:
4+x=8+0.2x
Subtract 0.2x from both sides:
0.8x=4
Divide by 0.8:
x=5
Therefore, 5 litres of water need to be added to the 40 litres of milk to achieve a mixture containing 20% water.