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Q.a certain mixture contains three chemicals P,Q,R are in the ratio 1/3:2/5:3/4. What is the quantity of each chemical in 2670 money the mixture.
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Q.a certain mixture contains three chemicals P,Q,R are in the ratio 1/3:2/5:3/4. What is the quantity of each chemical in 2670 money the mixture.
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Answer:
600 ml, 720 ml, 1350 ml
Step-by-step explanation:
Given P,Q,R are in the ratio 1/3 : 2/5 : 3/4.
Total mixture = 2670 ml.
Let the common ratio be x.
⇒ (x/3) + (2x/5) + (3x/4) = 2670
⇒ (x * 20 + 24x + 25x)/60 = 2670
⇒ 89x/60 = 2670
⇒ 89x = 160200
⇒ x = 1800.
Now,
∴ Quantity of P = (1/3) * x
= 600
∴ Quantity of Q = (2/5) * x
= 720.
∴ Quantity of R = (3/4) * x
= 1350 ml.
Therefore, Quantity of P,Q,R are 600 ml, 720 ml, 1350 ml.
Hope it helps!