★Given:-
★To find:-
★Solution:-
Assume,
As, B is twice as likely to win as C,
As,A is twice as likely to win as B,
⇒ 2×P(B) = 2× 2x = 4x.
Total probability of winning=1
Hence,
⇒ x + 2x + 4x = 1
⇒ 7x = 1
⇒ x = 1/7
Therefore,
→Probability of C = 1/7
→Probability of winning of B = 2x
⇒ 2 × (1/7)
⇒ 2/7
∴ Probability of B is 2/7
→Probability of winning of A=4x
⇒ 4 × (1/7)
⇒ 4/7
∴Probability of A = 4/7
The probabilities of A,B,C are 4/7,2/7,1/7 respectively.
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Verified answer
★Given:-
★To find:-
★Solution:-
Assume,
As, B is twice as likely to win as C,
As,A is twice as likely to win as B,
⇒ 2×P(B) = 2× 2x = 4x.
Total probability of winning=1
Hence,
⇒ x + 2x + 4x = 1
⇒ 7x = 1
⇒ x = 1/7
Therefore,
→Probability of C = 1/7
→Probability of winning of B = 2x
⇒ 2 × (1/7)
⇒ 2/7
∴ Probability of B is 2/7
→Probability of winning of A=4x
⇒ 4 × (1/7)
⇒ 4/7
∴Probability of A = 4/7
Hence,
The probabilities of A,B,C are 4/7,2/7,1/7 respectively.
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