Answer:
7/5
Step-by-step explanation:
Using the Pythagorean Theorem
Hypotenuse2 = Perpendicular2 + Base2
Hypotenuse2 = (3k)2 + (4k)2
= 9k2 + 16k2
= 25k2
So Hypotenuse = 5k
We know that
sin A = Perpendicular/ Hypotenuse
= 3k/5k
= 3/5
cos A = Base/ Hypotenuse
= 4k/5k
= 4/5
sin A + cosA= 3/5+4/5=7/5
thank
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Answers & Comments
Answer:
7/5
Step-by-step explanation:
Using the Pythagorean Theorem
Hypotenuse2 = Perpendicular2 + Base2
Hypotenuse2 = (3k)2 + (4k)2
= 9k2 + 16k2
= 25k2
So Hypotenuse = 5k
We know that
sin A = Perpendicular/ Hypotenuse
= 3k/5k
= 3/5
cos A = Base/ Hypotenuse
= 4k/5k
= 4/5
sin A + cosA= 3/5+4/5=7/5
[tex] \implies \: tan A = \frac{3}{4} \\ \\ pythagoras \: theoram \\ \\ \implies \boxed{ \pink{ { h}^{2} = {b}^{2} + {p}^{2} }} \\ \\ \implies \: h = \sqrt{ {3}^{2} + {4}^{2} } \\ \\ \implies \: h = \sqrt{25} \\ \\ \implies \: h = 5 \\ \\ \implies \sin A = \frac{p}{h} = \frac{3}{5} \\ \\ \implies \cos \: A = \frac{b}{h} = \frac{4}{5} \\ \\ \implies \sin A \: + \cos A = \frac{3}{5} + \frac{4}{5} \\ \\ \implies \: \frac{3 + 4}{5} \\ \\ \implies \: \frac{7}{5} [/tex]
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thank