For number 4:
Solving for
For number 5:
Let and be the measures of the other two angles of the pentagon.
Substituting the value of x, we get
Thus, the other two angles measure 72° and 108°.
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SOLUTION:
Recall:
For number 4:
Solving for![m, m,](https://tex.z-dn.net/?f=%20m%2C)
For number 5:
Let
and
be the measures of the other two angles of the pentagon.
Substituting the value of x, we get
Thus, the other two angles measure 72° and 108°.
Answer:
72° and 128°
Three angles of a pentagon are 105°, 135°, and 120°.
Let N represents the other 2 angles of the pentagon.
540° - (105° + 135° + 120°) = N
540° - 360° = N
180° = N
If the other two angles of the pentagon has a sum of 180°, find the measure of each using the ratio 2:3.
Let x be the angle measure.
2x + 3x = 180
5x = 180
=
x = 36°
Using x = 2 find the angle measures.
2x = 2(36) = 72°
3x = 3(36) = 108°
Therefore, the measures of the other two angles of the pentagon are 72° and 108° respectively.