Answer:
L , B length & width of floor
floor area = ( w+32)*w =200
w^2 +32w -200 =0
w = -32+ or - sqrt of ( 32 ^2 - 4*1* (-200)) /2
= -32 + or - sqrt of( 1024+800) /2
= -32 + or - sqrt of(1824) /2
= (-32 + or - 42.71) / 2 = 10.71 /2
= 5 .355 m
L = 5 .355 m +32 = 37 .355 m
Dimensions of the floors are L by W = 37 .355 m by 5 .355m
Hope this is helpful for you.
Step-by-step explanation:
Length = l
Width = w
Area = w * l
Given is that area is more than 200, and that l = w + 32
200 = w * l = w * (w + 32) = w² + 32w
w² + 32w - 200 = 0
Using quadratic equation method we find w = -16 + 2√114 or -16 - 2√114
Only the first has a positive value.
So possible dimensions are any dimensions where
l = w + 32 and w > -16 + 2√114 (or w > 5.354)
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Answers & Comments
Answer:
L , B length & width of floor
floor area = ( w+32)*w =200
w^2 +32w -200 =0
w = -32+ or - sqrt of ( 32 ^2 - 4*1* (-200)) /2
= -32 + or - sqrt of( 1024+800) /2
= -32 + or - sqrt of(1824) /2
= (-32 + or - 42.71) / 2 = 10.71 /2
= 5 .355 m
L = 5 .355 m +32 = 37 .355 m
Dimensions of the floors are L by W = 37 .355 m by 5 .355m
Hope this is helpful for you.
Step-by-step explanation:
Length = l
Width = w
Area = w * l
Given is that area is more than 200, and that l = w + 32
200 = w * l = w * (w + 32) = w² + 32w
w² + 32w - 200 = 0
Using quadratic equation method we find w = -16 + 2√114 or -16 - 2√114
Only the first has a positive value.
So possible dimensions are any dimensions where
l = w + 32 and w > -16 + 2√114 (or w > 5.354)
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