Verified answer

Given info : A 10 C of charge flows through

a wire in 5 minutes. The radius of the wire is 1 mm. It contains 5 × 10²² electrons per cm³.

To find : The current and drift velocity are ...

solution : we know, current is the rate of flowing of charge.

so, I = Q/t

here charge, Q = 10 C and time, t = 5 min = 5 × 60 = 300 sec

so, i = 10/300 = 1/30 = 0.033 A

Therefore the current through the wire is

0.033 A.

now drift velocity, v = i/neA [ formula ]

where I is current flowing through wire, n is number of electrons per unit volume, e is charge on electron and A is cross section area.

n = 5 x 10²² /cm³ = 5 × 10^28 /m³

e = 1.6 × 10^-19 C

A = πr² = 3.14 × (1 × 10−³)² = 3.14 × 10-6 m² X = (0.033)/(5 × 10^28 × 1.6 × 10^-19 × 3.14 SO, V = × 10^-6)

= (0.033)/(5 × 1.6 × 3.14 × 10³) X

= (0.033)/(5 × 1.6 × 3.14 × 10³) X= 0.0013 × 10 -³ m/s = 1.3 x 10-6 m/s

= (0.033)/(5 × 1.6 × 3.14 × 10³) X= 0.0013 × 10 -³ m/s = 1.3 x 10-6 m/sTherefore the drift velocity of electron is

= (0.033)/(5 × 1.6 × 3.14 × 10³) X= 0.0013 × 10 -³ m/s = 1.3 x 10-6 m/sTherefore the drift velocity of electron is1.3 x 10-6 m/s.

= (0.033)/(5 × 1.6 × 3.14 × 10³) X= 0.0013 × 10 -³ m/s = 1.3 x 10-6 m/sTherefore the drift velocity of electron is1.3 x 10-6 m/s.also read similar questions: A current of 4A is flowing in a copper wire. If the same current is allowed to flow through another copper wire of doubl...