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Step-by-step explanation:

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Answer:

Given :-

• The rate of interest is 2 1/4 %, time period is 3 years and the simple interest is Rs 50.

To Find :-

• What is the principal amount.

Formula Used :-

[tex]\clubsuit[/tex] Principal Formula :

[tex]\bigstar \: \: \sf\boxed{\bold{\pink{P =\: \dfrac{S.I \times 100}{R \times n}}}}\: \: \: \bigstar\\[/tex]

where,

• P = Principal
• S.I = Simple Interest
• R = Rate of Interest
• n = Time Period

Solution :-

Given :

• Rate of Interest = 2 ¼ %
• Time Period = 3 years
• Simple Interest = Rs 50

According to the question by using the formula we get,

[tex]\implies \bf P =\: \dfrac{S.I \times 100}{R \times n}\\[/tex]

[tex]\implies \sf P =\: \dfrac{50 \times 100}{2\dfrac{1}{4} \times 3}[/tex]

[tex]\implies \sf P =\: \dfrac{5000}{\bigg(2 + \dfrac{1}{4}\bigg) \times 3}[/tex]

[tex]\implies \sf P =\: \dfrac{5000}{\bigg(\dfrac{2 \times 4 + 1}{4}\bigg) \times 3}[/tex]

[tex]\implies \sf P =\: \dfrac{5000}{\bigg(\dfrac{8 + 1}{4}\bigg) \times 3}[/tex]

[tex]\implies \sf P =\: \dfrac{5000}{\dfrac{9}{4} \times 3}[/tex]

[tex]\implies \sf P =\: \dfrac{5000}{\dfrac{9 \times 3}{4}}[/tex]

[tex]\implies \sf P =\: \dfrac{5000}{\dfrac{27}{4}}[/tex]

[tex]\implies \sf P =\: \dfrac{5000}{1} \times \dfrac{4}{27}[/tex]

[tex]\implies \sf P =\: \dfrac{20000}{27}[/tex]

[tex]\implies \sf\bold{\red{P =\: Rs\: 740.74}}[/tex]

[tex]\therefore[/tex] The principal amount is Rs 740.74 .