Answer:

D =4

√(x+3)2+y2=4

(x+3)2+y2=16

x2+6x+9+y2−16=0

x2+y2+6x−7=0 -----(i)

D = 4

√(x−3)2+y2=4

x2−6x+9+y2=16

x2+y2−6x−7=0 -----(ii)

From (i) and (ii)

6x−7=−6x−7

x=0

Put x=0 in (i)

y=√7

I hope it's help you