Answer:
Emf of the reaction is + 0 . 6 1 V
Explanation:
Cathode−CCl2++2e _−→CCl
Anode− 2 A g→2 A g++2e _−
−−−−−−−−−
Cell reaction Cu2++2 A g→2 A g++Cu
Ecell0=+ 0 . 4 6 v
Ecell=0 . 4 6V _−20.0591log[Cu2+][Ag+]2Ecell=0 . 4 6V _−20.0591log[10−1][10−3]2Ecell=+ 0 . 6 1 V
Thus the Emf of the reaction is + 0 . 6 1 V
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Answer:
Emf of the reaction is + 0 . 6 1 V
Explanation:
Cathode−CCl2++2e _−→CCl
Anode− 2 A g→2 A g++2e _−
−−−−−−−−−
Cell reaction Cu2++2 A g→2 A g++Cu
Ecell0=+ 0 . 4 6 v
Ecell=0 . 4 6V _−20.0591log[Cu2+][Ag+]2Ecell=0 . 4 6V _−20.0591log[10−1][10−3]2Ecell=+ 0 . 6 1 V
Thus the Emf of the reaction is + 0 . 6 1 V