The potential energy of an object is given by
where:
PE = potential energy
m = mass
g = acceleration due to gravity = 9.8 m/s²
h = height
Note: 500 g = 0.5 kg
PE = mgh
PE = (0.5 kg)(9.8 m/s²)(30 m)
Therefore, the potential energy of the ripe mango fruit is 147 J.
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The potential energy of an object is given by
where:
PE = potential energy
m = mass
g = acceleration due to gravity = 9.8 m/s²
h = height
Solving for PE
Note: 500 g = 0.5 kg
PE = mgh
PE = (0.5 kg)(9.8 m/s²)(30 m)
Therefore, the potential energy of the ripe mango fruit is 147 J.