[tex] \alpha nswer \: \\ 3x + 4z + 96y \\ 3(2) + 4(9) + 96(1) \\ 6 + 36 + 96 \\ 6 + 132 \\ = 138 \\ \\ thank \: you[/tex]

138

■ Given :

 [tex]\sf{3x+4z+96y}[/tex]

■ To find :

• x = 2
• y = 1
• z = 9

■ Solution/Concept :

• Substitute each value into the expression

[tex]\implies\sf{3(2)+4(9)+96(1)}\\\\\implies\sf{6+36+96}\\\\\implies\sf{6+132}\\\\\implies\boxed{\sf{138}}[/tex]

And 138 is your Answer !!