Answer:
3x^2 + 27x + 20
Step-by-step explanation:
Using identity: x^2 + ( a + b)x + ab
3x^2 + ( 4 + 5)3x + (4)(5)
Hope it helps
Given (3x + 4) (3x – 5)
3x (3x – 5) + 4 (3x – 5)
(3x )² – (5 × 3x) + (4 × 3x) – (5 × 4)
9x² – 15x + 12x – 20
9x² – 3x – 20
9x² – (15 – 12)x – 20
(3x – 5)(3x + 4)
So
3x – 5 = 0 or
3x + 4 = 0
x = 5/3 or x = -4/3
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Verified answer
Answer:
3x^2 + 27x + 20
Step-by-step explanation:
Using identity: x^2 + ( a + b)x + ab
3x^2 + ( 4 + 5)3x + (4)(5)
3x^2 + 27x + 20
Hope it helps
Given (3x + 4) (3x – 5)
3x (3x – 5) + 4 (3x – 5)
(3x )² – (5 × 3x) + (4 × 3x) – (5 × 4)
9x² – 15x + 12x – 20
9x² – 3x – 20
9x² – (15 – 12)x – 20
9x² – 15x + 12x – 20
3x (3x – 5) + 4 (3x – 5)
(3x – 5)(3x + 4)
So
3x – 5 = 0 or
3x + 4 = 0
x = 5/3 or x = -4/3