5.) f( x ) = x3 + 46.) f(x) = 3 x3 - 27.) f(x)= x+2 / x + 48.) f(x)= 2x+3 /3x +19.) f(x) = √x+110.) f(x) = √x² +2. Created by haley272020. Math

3x +19.) f(x) = √x+110.) f(x) = √x² +2...

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haley272020 @haley272020

October 2022 1 15 Report

5.) f( x ) = x3 + 4
6.) f(x) = 3 x3 - 2
7.) f(x)= x+2 / x + 4
8.) f(x)= 2x+3 /3x +1
9.) f(x) = √x+1
10.) f(x) = √x² +2

Answers & Comments

gadorangel09

Answer:

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$5.)f(x) = {x}^{3} + 4 \\ y = {x}^{3} + 4 \\ x = {y}^{3} + 4 \\ x - 4 = {y}^{3} \\ \sqrt[3]{x - 4} = y \\ {f}^{ - 1}(x) = \sqrt[3]{x - 4}$

$6.)f(x) = 3 {x}^{3} - 2 \\ y = 3 {x}^{3} - 2 \\ x = 3 {y}^{3} - 2 \\ x + 2 = 3 {y}^{3} \\ \frac{x + 2}{3} = {y}^{3} \\ \sqrt[3]{ \frac{x + 2}{3} } = y \\ {f}^{ - 1} (x) = \sqrt[3]{ \frac{x + 2}{3} }$

$9.)f(x) = \sqrt{x + 1} \\ y = \sqrt{x + 1} \\ x = \sqrt{y + 1} \\ {x}^{2} = y + 1 \\ {x}^{2} - 1 = y \\ {f}^{ - 1} (x) = {x}^{2} - 1$

$10.)f(x) = \sqrt{ {x}^{2} + 2} \\ y = \sqrt{ {x}^{2} + 2 } \\ x = \sqrt{ {y}^{2} + 2 } \\ {x}^{2} = {y}^{2} + 2 \\ {x}^{2} - 2 = {y}^{2} \\ \sqrt{ {x}^{2} - 2 } = y \\ {f}^{ - 1} (x) = \sqrt{ {x}^{2} - 2 }$

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haley272020 tenchuuuu❤️

gadorangel09 pabrainliest naman HAHA btw yung 7 and 8 nasa isa yung may pic

gadorangel09 yung 7. (x+1)/(x+4)? tas 8. (2x+3)/(3x+1)?

haley272020 ou

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