[tex] \large \sf Question [/tex]
Spherical ball of clay with radius 2 inches contain exactly enough play to make brick , how many such brick made using amount of clay in spherical ball with radius 4 inches.
{ Volume V of sphere with radius R given by V = 4/3πr³ }
→Explain properly
→Don't Spam
Answers & Comments
Verified answer
Answer:
8 bricks can be made using the given spherical ball of clay.
Step-by-step explanation:
To Find:
Formula used:
where,
R is radius of the sphere.
Solution:
Let the volume of sphere with radius of 2 inches be V1.
Using the formula, we get
V1 = 4/3π(2)^3
V1 = 4(8)π/3
V1 = 32π/3 cubic inches....(1)
Let the volume of spherical ball with radius 4 inches be V2.
V2 = 4/3π(4)^3
V2 = 4(64)π/3
V2 = 256π/3 cubic inches....(2)
Since Spherical ball of clay with 2 inches radius has enough clay to make 1 brick
Therefore, No. of brick = (2)/(1)
No. of brick = (256π/3)/(32π/3)
No. of brick = 256/32
No. of brick = 8
So, 8 bricks can be made out of the given spherical ball
answer:-
To solve this problem, we need to compare the volumes of the two spheres and calculate how many times the smaller sphere can fit into the larger one.
The volume of a sphere with radius R is given by the formula V = (4/3)πR³.
Let's calculate the volume of the smaller sphere with a radius of 2 inches:
V₁ = (4/3)π(2³)
= (4/3)π(8)
= (32/3)π
Now, let's calculate the volume of the larger sphere with a radius of 4 inches:
V₂ = (4/3)π(4³)
= (4/3)π(64)
= (256/3)π
To find out how many times the smaller sphere can fit into the larger one, we divide the volume of the larger sphere by the volume of the smaller sphere:
Number of bricks = V₂ / V₁
= (256/3)π / (32/3)π
= 256/32
= 8
Therefore, using the amount of clay in a spherical ball with a radius of 4 inches, you can make 8 bricks of the same size as the ones made using the smaller sphere with a radius of 2 inches
thank you ❤️‼️