Verified answer

Given that :

• Siya got two ropes
• Length of the ropes = 1/2m and 5/3m.

To Find :

• The total length of both ropes.

Solution :

[tex] \sf \implies \dfrac{1}{2} + \dfrac{5}{3}[/tex]

[tex] \sf \implies \dfrac{1 { \: }^{ \times 3 } }{ 2} + \dfrac{5 { \: }^{ \times 2} }{3 }[/tex]

[tex] \frak{lcm = 6}[/tex]

[tex] \frak{[2 × 3 = 6]}[/tex]

[tex] \frak{[3 × 2 = 6]}[/tex]

[tex] \sf \implies \dfrac{3 + 10}{6} [/tex]

[tex] \sf \implies \dfrac{13}{6} [/tex][tex] \sf = 2\dfrac{1}{6} \: \: m[/tex]

or :

[tex] \sf \implies \underline{ \: 2.166\: } \: m[/tex]

But since the values in the question were given in the form of improper fractions, so we give the answer in the same way.

[tex] \therefore \: [/tex]The total length of both ropes =

[tex]{ \frak{ {\dfrac{13}{6}} \: m.}}[/tex]