Let ABCD in square AB=CD=DA=BC=?P=(3,7)draw PM⊥ABM is mid point of AB
Let ABCD in square AB=CD=DA=BC=?P=(3,7)draw PM⊥ABM is mid point of ABSo, AM=MB=PM=?
Let ABCD in square AB=CD=DA=BC=?P=(3,7)draw PM⊥ABM is mid point of ABSo, AM=MB=PM=?diagonal is parallel to y = x, its sides
Let ABCD in square AB=CD=DA=BC=?P=(3,7)draw PM⊥ABM is mid point of ABSo, AM=MB=PM=?diagonal is parallel to y = x, its sidesare parallel a to coordinate axis
Let ABCD in square AB=CD=DA=BC=?P=(3,7)draw PM⊥ABM is mid point of ABSo, AM=MB=PM=?diagonal is parallel to y = x, its sidesare parallel a to coordinate axis∴ M = (3, 5)
Let ABCD in square AB=CD=DA=BC=?P=(3,7)draw PM⊥ABM is mid point of ABSo, AM=MB=PM=?diagonal is parallel to y = x, its sidesare parallel a to coordinate axis∴ M = (3, 5)⇒ A= (3 - 2, 5) = (1, 5)
Let ABCD in square AB=CD=DA=BC=?P=(3,7)draw PM⊥ABM is mid point of ABSo, AM=MB=PM=?diagonal is parallel to y = x, its sidesare parallel a to coordinate axis∴ M = (3, 5)⇒ A= (3 - 2, 5) = (1, 5)B = (3 + 2 + 5) = (5, 5)
Let ABCD in square AB=CD=DA=BC=?P=(3,7)draw PM⊥ABM is mid point of ABSo, AM=MB=PM=?diagonal is parallel to y = x, its sidesare parallel a to coordinate axis∴ M = (3, 5)⇒ A= (3 - 2, 5) = (1, 5)B = (3 + 2 + 5) = (5, 5)C = (3 + 5, 7 + 2) = (8, 9)
Let ABCD in square AB=CD=DA=BC=?P=(3,7)draw PM⊥ABM is mid point of ABSo, AM=MB=PM=?diagonal is parallel to y = x, its sidesare parallel a to coordinate axis∴ M = (3, 5)⇒ A= (3 - 2, 5) = (1, 5)B = (3 + 2 + 5) = (5, 5)C = (3 + 5, 7 + 2) = (8, 9)D = (3 - 2, 7 + 2) = (1, 9)
Answers & Comments
Answer:
Side of square field = 4 2/3 m = 14/3 m
Therefore,
Area = (14/3)² m²
= 196/9 m²
= 21 7/9 m²
So, its area is 21 7/9 m².
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Let ABCD in square
Let ABCD in square AB=CD=DA=BC=?
Let ABCD in square AB=CD=DA=BC=?P=(3,7)
Let ABCD in square AB=CD=DA=BC=?P=(3,7)draw PM⊥AB
Let ABCD in square AB=CD=DA=BC=?P=(3,7)draw PM⊥ABM is mid point of AB
Let ABCD in square AB=CD=DA=BC=?P=(3,7)draw PM⊥ABM is mid point of ABSo, AM=MB=PM=?
Let ABCD in square AB=CD=DA=BC=?P=(3,7)draw PM⊥ABM is mid point of ABSo, AM=MB=PM=?diagonal is parallel to y = x, its sides
Let ABCD in square AB=CD=DA=BC=?P=(3,7)draw PM⊥ABM is mid point of ABSo, AM=MB=PM=?diagonal is parallel to y = x, its sidesare parallel a to coordinate axis
Let ABCD in square AB=CD=DA=BC=?P=(3,7)draw PM⊥ABM is mid point of ABSo, AM=MB=PM=?diagonal is parallel to y = x, its sidesare parallel a to coordinate axis∴ M = (3, 5)
Let ABCD in square AB=CD=DA=BC=?P=(3,7)draw PM⊥ABM is mid point of ABSo, AM=MB=PM=?diagonal is parallel to y = x, its sidesare parallel a to coordinate axis∴ M = (3, 5)⇒ A= (3 - 2, 5) = (1, 5)
Let ABCD in square AB=CD=DA=BC=?P=(3,7)draw PM⊥ABM is mid point of ABSo, AM=MB=PM=?diagonal is parallel to y = x, its sidesare parallel a to coordinate axis∴ M = (3, 5)⇒ A= (3 - 2, 5) = (1, 5)B = (3 + 2 + 5) = (5, 5)
Let ABCD in square AB=CD=DA=BC=?P=(3,7)draw PM⊥ABM is mid point of ABSo, AM=MB=PM=?diagonal is parallel to y = x, its sidesare parallel a to coordinate axis∴ M = (3, 5)⇒ A= (3 - 2, 5) = (1, 5)B = (3 + 2 + 5) = (5, 5)C = (3 + 5, 7 + 2) = (8, 9)
Let ABCD in square AB=CD=DA=BC=?P=(3,7)draw PM⊥ABM is mid point of ABSo, AM=MB=PM=?diagonal is parallel to y = x, its sidesare parallel a to coordinate axis∴ M = (3, 5)⇒ A= (3 - 2, 5) = (1, 5)B = (3 + 2 + 5) = (5, 5)C = (3 + 5, 7 + 2) = (8, 9)D = (3 - 2, 7 + 2) = (1, 9)