27. Three solid cubes of type A and three
solid cubes of type B are melted to form
a cube. If the lengths of diagonals of
cubes of type A and type B are 4/3cm
and 8/3cm respectively, then find the
lateral surface area of the cube so
formed.
(A) 625 cm? (B) 864 cm?
(C) 576 cm
(D) 784 cm
(E) None of these
solid cubes of type B are melted to form
a cube. If the lengths of diagonals of
cubes of type A and type B are 4/3cm
and 8/3cm respectively, then find the
lateral surface area of the cube so
formed.
(A) 625 cm? (B) 864 cm?
(C) 576 cm
(D) 784 cm
(E) None of these
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Length of diagonal=a√3
type A's diagonal=a√3=4/3-----(1)
a=4/3÷√3
a=4/3√3=2.3094010767585
type B's diagonal=a√3=8/3------(2)
a√3=8/3
a=8/3÷√3
a=8/3√3=4.6188021535170
Lateral surface=4a^2
type A
4×(2.3094010767585)^2= 21.333333333333276835469289
type B
4×(4.6188021535170)^2= 85.333333333333107341877156
Lateral surface of cube formed by A and B is
type A + type B lateral surface
3×21.333333333333276835469289+3×85.333333333333107341877156
=319.999999999999152532039335
319.9 is not there so none of these
I think check other's answer too