Answer:

I don't know what is (53 1/2 33 4/5 32 2/3)

PROBLEM:

Given two sides of a triangle and its perimeter, find the unknown side.

\begin{gathered} side_{1} = 7 \frac{3}{4} cm \\ side_{2} = 4 \frac{2}{3} cm \\ perimeter = 18cm \end{gathered}

side

1

=7

4

3

cm

side

2

=4

3

2

cm

perimeter=18cm

SOLUTION:

\begin{gathered} p_{triangle} = side_{1} + side_{2} +side_{3} \\ 18 = 7 \frac{3}{4} + 4 \frac{2}{3} + x \\ 18 = \frac{31}{4} + \frac{14}{3} + x \\ 18 = \frac{(31 \times 3) + (14 \times 4) + (x \times 12)}{12} \\ 18 = \frac{93 + 56 + 12x}{12} \\ 18 = \frac{149 + 12x}{12} \\ 12 \times 18 = 149 + 12x \\ 216 = 149 + 12x \\ 216 - 149 = 12x \\ 12x = 67 \\ x = \frac{67}{12}cm \: \: or \: \: 5 \frac{7}{12} cm\end{gathered}

p

triangle

=side

1

+side

2

+side

3

18=7

4

3

+4

3

2

+x

18=

4

31

+

3

14

+x

18=

12

(31×3)+(14×4)+(x×12)

18=

12

93+56+12x

18=

12

149+12x

12×18=149+12x

216=149+12x

216−149=12x

12x=67

x=

12

67

cmor5

12

7

cm