Answer:

Hello,

we know that

(x^3+y^3+z^3 - 3xyz)= (x+y+z)(x^2+y^2+z^2-xy-yz-zx)

therefore, x^3+y^3+z^3 = {(x+y+z)(x^2+y^2+z^2-xy-yz-zx)+3xyz}

Hence, (x^3+y^3+z^3)^1/3=

{(x+y+z)(x^2+y^2+z^2-xy-yz-zx)+3xyz}^1/3 ans.

Thank you! !