Answer:
the answer is 12m.
Explanation:
If we draw the diagram according to the question, it is becoming right angle triangle,
As we know that we can apply the formula of Pythagoras theorem in right angle triangle ,
Pythagoras theorem is,
[tex] {H }^{2} = {P}^{2} + { B}^{2} \\ [/tex]
where H is height,
P is perpendicular
B is base
Now from the diagram, the values are coming as
H = 20m
P = 16m
B = ?
[tex] {H }^{2} = {P}^{2} + { B}^{2} \\ \\ ( {20}^{2} ) = ( {16}^{2} ) + {B}^{2} \\ 400 = 256 + {B}^{2} \\ 400 - 256 = {B}^{2} \\ 144 = {B}^{2} \\ B = \sqrt{144} \\ B = 12m[/tex]
therefore,the distance between the base of the wall and foot of the ladder is 12m.
hope it helps.
Hope It Helps...!
Have a great day ahead...!
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Verified answer
Answer:
the answer is 12m.
Explanation:
If we draw the diagram according to the question, it is becoming right angle triangle,
As we know that we can apply the formula of Pythagoras theorem in right angle triangle ,
Pythagoras theorem is,
[tex] {H }^{2} = {P}^{2} + { B}^{2} \\ [/tex]
where H is height,
P is perpendicular
B is base
Now from the diagram, the values are coming as
H = 20m
P = 16m
B = ?
[tex] {H }^{2} = {P}^{2} + { B}^{2} \\ \\ ( {20}^{2} ) = ( {16}^{2} ) + {B}^{2} \\ 400 = 256 + {B}^{2} \\ 400 - 256 = {B}^{2} \\ 144 = {B}^{2} \\ B = \sqrt{144} \\ B = 12m[/tex]
therefore,the distance between the base of the wall and foot of the ladder is 12m.
hope it helps.
Hope It Helps...!
Have a great day ahead...!