Answer:
To multiply (-6ab²/5) by (65a²b/36), we can follow these steps:
Step 1: Simplify both fractions by canceling out any common factors:
(-6ab²/5) = (-2ab²/5) x 3
(65a²b/36) = (5a²b/4) x (13/9)
Step 2: Multiply the numerators together and multiply the denominators together:
((-2ab²/5) x 3) x ((5a²b/4) x (13/9))
= (-2ab² x 3 x 5a²b x 13) / (5 x 4 x 9)
= (-6 x 65 a^3 b^3) / 180
= (-13/18) a^3 b^3
Therefore, (-6ab²/5) multiplied by (65a²b/36) is equal to (-13/18) a^3 b^3.
[tex] \frac{ - 6a {b}^{2} }{5} \times \frac{65 {a}^{2}b }{36} \\ \\ \frac{ - a {b}^{2} }{1} \times \frac{13 {a}^{2}b }{6} \\ \frac{ {13a}^{3} {b}^{3} }{6} [/tex]
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Answers & Comments
Answer:
To multiply (-6ab²/5) by (65a²b/36), we can follow these steps:
Step 1: Simplify both fractions by canceling out any common factors:
(-6ab²/5) = (-2ab²/5) x 3
(65a²b/36) = (5a²b/4) x (13/9)
Step 2: Multiply the numerators together and multiply the denominators together:
((-2ab²/5) x 3) x ((5a²b/4) x (13/9))
= (-2ab² x 3 x 5a²b x 13) / (5 x 4 x 9)
= (-6 x 65 a^3 b^3) / 180
= (-13/18) a^3 b^3
Therefore, (-6ab²/5) multiplied by (65a²b/36) is equal to (-13/18) a^3 b^3.
Verified answer
Answer:
[tex] \frac{ - 6a {b}^{2} }{5} \times \frac{65 {a}^{2}b }{36} \\ \\ \frac{ - a {b}^{2} }{1} \times \frac{13 {a}^{2}b }{6} \\ \frac{ {13a}^{3} {b}^{3} }{6} [/tex]