rationalize the denominator of 4/3+√(5). Created by Mohit123Sharma. Math

3+√(5)...

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$\frac{4}{3 + \sqrt{5} } = \frac{4}{3 + \sqrt{5} } \times \frac{3 - \sqrt{5} }{3 - \sqrt{5} } \\ \\ = \frac{4(3 - \sqrt{5}) }{ {3}^{2} - {( \sqrt{5} )}^{2} } \\ \\ = \frac{4(3 - \sqrt{5} )}{9 - 5} \\ \\ = \frac{4(3 - \sqrt{5}) }{4} \\ \\ = 3 - \sqrt{5}$

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