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In a △ABC, A:B:C=3:5:4, then a+b+c
2
is equal to:
Medium
Solution
verified
Verified by Toppr
Correct option is C)
In a △ABC, A:B:C=3:5:4 (given)
Let x be the variable.
∴3x+5x+4x=180
∘
⇒ x=15
⇒ A=45
⇒ B=75
⇒ C=60
Using sine law,
⇒
sinA
a
=
sinB
b
sinC
c
(1+
3
)
2c
⇒a=
2b
⇒c=
⇒a+b+c
1+
+b+
Upon simplification, we get:
⇒a+b+
c=3b
i Hopw you like it
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Answers & Comments
Answer:
search-icon-header
Search for questions & chapters
search-icon-image
Question
Bookmark
In a △ABC, A:B:C=3:5:4, then a+b+c
2
is equal to:
Medium
Solution
verified
Verified by Toppr
Correct option is C)
In a △ABC, A:B:C=3:5:4 (given)
Let x be the variable.
∴3x+5x+4x=180
∘
⇒ x=15
∘
⇒ A=45
∘
⇒ B=75
∘
⇒ C=60
∘
Using sine law,
⇒
sinA
a
=
sinB
b
=
sinC
c
a
2
=
(1+
3
)
2
2
b
=
3
2c
⇒a=
(1+
3
)
2b
⇒c=
(1+
3
)
2
b
3
⇒a+b+c
2
=
1+
3
2b
+b+
1+
3
2b
3
Upon simplification, we get:
⇒a+b+
2
c=3b
c=3b
i Hopw you like it