We have,
x
2/3
+x
1/3
−2=0
Let x
=y
then,
y
2
+y−2=0
+(2−1)y−2=0
+2y−1y−2=0
y(y+2)−1(y+2)=0
(y+2)(y−1)=0
If y+2=0, y−1=0
y=−2, y=1
=−2, x
=1
x=(−2)
3
, x=1
x=−8, x=1
answer is -1.
Step-by-step explanation:
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Answers & Comments
Verified answer
We have,
x
2/3
+x
1/3
−2=0
Let x
1/3
=y
then,
x
2/3
+x
1/3
−2=0
y
2
+y−2=0
y
2
+(2−1)y−2=0
y
2
+2y−1y−2=0
y(y+2)−1(y+2)=0
(y+2)(y−1)=0
If y+2=0, y−1=0
y=−2, y=1
x
1/3
=−2, x
1/3
=1
x=(−2)
3
, x=1
3
x=−8, x=1
answer is -1.
Step-by-step explanation:
pls. mark me as brain list