Answer:

\(x = \frac{53}{8}\).

Step-by-step explanation:

It seems like there might be some formatting issues or typos in the provided expressions. However, I'll try to interpret and solve the expressions based on what I understand.

1) \(x^2 - 4x^2 + 4 = 0\)

To solve this quadratic equation, let's identify the coefficients:

\(a = 1\), \(b = -4\), and \(c = 4\).

Now, use the quadratic formula \(b^2 - 4ac\) and write the answer separately:

\[b^2 - 4ac = (-4)^2 - 4(1)(4) = 16 - 16 = 0\]

Therefore, the expression \(b^2 - 4ac\) for \(x^2 - 4x^2 + 4\) is equal to 0.

2) \(3.7^2 + \frac{6}{3} = 0\)

This expression doesn't seem to be a quadratic equation. It looks like an expression to be evaluated.

\[3.7^2 + \frac{6}{3} = 13.69 + 2 = 15.69\]

So, the value of the expression \(3.7^2 + \frac{6}{3}\) is 15.69.

3) \(9^2 - 4(1)(2x + 5) = 8\)

It seems there might be a typo or misunderstanding in the expression. Assuming it's \(9^2 - 4(1)(2x + 5) = 8\), let's simplify it:

\[81 - 4(2x + 5) = 8\]

Distribute the 4:

\[81 - 8x - 20 = 8\]

Combine like terms:

\[-8x + 61 = 8\]

Subtract 61 from both sides:

\[-8x = -53\]

Divide by -8:

\[x = \frac{53}{8}\]

Answer:

It seems like there are some typos and errors in your input. Let's clarify and correct them:

1. For the quadratic equation \(1x^2 - 4x + 4 = 0\):

- Identify the values of \(a\), \(b\), and \(c\): \(a = 1\), \(b = -4\), \(c = 4\).

- Calculate \(b^2 - 4ac\): \((-4)^2 - 4(1)(4) = 16 - 16 = 0\).

2. For the expression \(2x^2 + \frac{77}{10} = 0\), there seems to be a typo. Please provide the correct expression.

3. For the equation \(3.7^2 + \frac{6}{3} = 0\), it seems like there might be a mistake. Check the equation and provide the correct values.

4. For the equation \(9x^2 - 4x + 5 = 8\):

- Identify the values of \(a\), \(b\), and \(c\): \(a = 9\), \(b = -4\), \(c = 5\).

- Calculate \(b^2 - 4ac\): \((-4)^2 - 4(9)(5)\).

Step-by-step explanation:

Please correct the expressions, and I'll help you with the calculations.