Answer:
Step-by-step explanation:
Step 1. Transform the equation into linear
function.
2x-5y=32
=-5y=-2x+32
Step 2. Since the value of x is 6, you may now
substitute to get the value of y.
-5y=-2x+32
=-5y=-2(6)+32
=-5y=-12+32
=-5y=20
__ __
-5 -5
=y=-4
*paki btainliest na lang po
Is 2x-5y=32, 2x+3y=0 solvable graphically?
:
Yes, find point of intersection using elimination
2x - 5y = 32
2x + 3y = 0
------------------ Subtraction eliminates x, find y
0 - 8y = 32
y = 32/-8
y = -4
find x using the 1st equation
2x - 5(-4) = 32
2x + 20 = 32
2x = 32 - 20
2x = 12
x = 12/2
x = 6
:]
Check solutions in 2nd equation
2(6) + 3(-4) = 0
12 - 12 = 0
The lines of the two equations will intersect a x=6, y=-4
Copyright © 2024 EHUB.TIPS team's - All rights reserved.
Answers & Comments
Answer:
The value of y is -4.
Step-by-step explanation:
Step 1. Transform the equation into linear
function.
2x-5y=32
=-5y=-2x+32
Step 2. Since the value of x is 6, you may now
substitute to get the value of y.
-5y=-2x+32
=-5y=-2(6)+32
=-5y=-12+32
=-5y=20
=-5y=20
__ __
-5 -5
=y=-4
*paki btainliest na lang po
Answer:
Is 2x-5y=32, 2x+3y=0 solvable graphically?
:
Yes, find point of intersection using elimination
2x - 5y = 32
2x + 3y = 0
------------------ Subtraction eliminates x, find y
0 - 8y = 32
y = 32/-8
y = -4
:
find x using the 1st equation
2x - 5(-4) = 32
2x + 20 = 32
2x = 32 - 20
2x = 12
x = 12/2
x = 6
:]
Check solutions in 2nd equation
2(6) + 3(-4) = 0
12 - 12 = 0
:
The lines of the two equations will intersect a x=6, y=-4