From an elevated point A,a stone is projected upwards when the stone reaches a distance h below A,its velocity is double of what it wad at a height above A the greatest height attained by the stone is nh/3 what is the value of n?
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Answer:
Explanation:
Distance=h
Initial velocity of stone =u
Velocity at point B, "h" above A is :
Vb²=u²-2gh Vb=√(u2-2gh)
velocity at point C below "h" Vc²=u2-2g(-h)
vc²=u2+2ghvc
=√(u2+2gh)
But according to given :
Vc²=4Vb²
(√(u1+2gh)²=4√(u2-2gh)²
u²+2gh=4u²-8gh
u²=10gh/3
Maximum height attained by stone:
Hmax=u/2g
=10gh /3x2g=5h/3
..Maximum height attained by stone is
5h/3