3. What is the smallest number by which 675 should be multiplied so that the product is a perfect cube?
4. What is the smallest number by which 2916 should be divided so that the quotient is a perfect cube
5. Write cubes of five natural numbers which are multiples of 3 and verify the following: The cube of a natural number which is a multiple of 3 is a multiple of 27'.
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Verified answer
Step-by-step explanation:
3. To find the smallest number by which 675 should be multiplied to get a perfect cube, we need to prime factorize 675.
675 = 3 × 3 × 3 × 5 × 5 × 5
To make it a perfect cube, we need to multiply it by the missing prime factors. In this case, we need to multiply it by 3 × 5 × 5 = 75.
So, the smallest number by which 675 should be multiplied to get a perfect cube is 75.
4. To find the smallest number by which 2916 should be divided to get a perfect cube, we need to prime factorize 2916.
2916 = 2 × 2 × 3 × 3 × 3 × 3 × 3 × 3
To make it a perfect cube, we need to divide it by the repeated prime factors. In this case, we need to divide it by 2 × 3 × 3 = 18.
So, the smallest number by which 2916 should be divided to get a perfect cube is 18.
5. Let's write the cubes of five natural numbers that are multiples of 3:
3³ = 27
6³ = 216
9³ = 729
12³ = 1728
15³ = 3375
Now, let's verify the statement "The cube of a natural number which is a multiple of 3 is a multiple of 27."
If we take any of the numbers we listed above and divide it by 27, we will get a whole number. For example, 216 divided by 27 is 8, and 3375 divided by 27 is 125.
So, the statement "The cube of a natural number which is a multiple of 3 is a multiple of 27" is verified.
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