Answer:
Formula:
Acceleration = Net force/mass or A = F/m
Solution:
A = F/m
= 200 N/300 kg
= 0.666667 m/s²
Therefore, the acceleration of a jeepney with a net force 200 N and a mass of 300 kg is 0.666667 m/s².
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Answer:
Formula:
Acceleration = Net force/mass or A = F/m
Solution:
A = F/m
= 200 N/300 kg
= 0.666667 m/s²
Therefore, the acceleration of a jeepney with a net force 200 N and a mass of 300 kg is 0.666667 m/s².
Pa brainliest lods