3. the area of a rectangular is 120 sa.cm. if the length is increased by 5 cm and the width is decreased by 2cm, the area remains the same. what the dimensions of the rectangular?
4. a wire a length of 40 cm is to form a rectangular with an area of 96 sa.cm. what are the dimensions of the rectangle?
5. the size of a television is 40 inches. if the area of the screen is 683 sq. inches what are the approximate length and with of the television screen? note that the size of a television is given by the diagonal of the screen
4. a wire a length of 40 cm is to form a rectangular with an area of 96 sa.cm. what are the dimensions of the rectangle?
5. the size of a television is 40 inches. if the area of the screen is 683 sq. inches what are the approximate length and with of the television screen? note that the size of a television is given by the diagonal of the screen
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3. Let's assume the length of the rectangle is L and the width is W. The area of the rectangle is given by the formula A = L * W.
Given that the area of the rectangle is 120 square centimeters, we have the equation L * W = 120.
According to the problem, if the length is increased by 5 cm and the width is decreased by 2 cm, the area remains the same. So we have the new dimensions (L + 5) and (W - 2), and the new area is still 120 square centimeters.
Setting up the equation with the new dimensions, we have (L + 5) * (W - 2) = 120.
Simplifying the equation, we get L * W + 5L - 2W - 10 = 120.
Since L * W = 120, the equation becomes 120 + 5L - 2W - 10 = 120.
Simplifying further, we have 5L - 2W = 10.
To find the dimensions of the rectangle, we can solve this equation along with the equation L * W = 120. However, there are multiple possible solutions, so we need additional information to determine the specific dimensions.
4. Let's assume the length of the rectangle is L and the width is W. The area of the rectangle is given by the formula A = L * W.
Given that the area of the rectangle is 96 square centimeters, we have the equation L * W = 96.
We are also given that the wire has a length of 40 cm, which is equal to the perimeter of the rectangle (2L + 2W).
Setting up the equation with the perimeter, we have 2L + 2W = 40.
Simplifying the equation, we get L + W = 20.
To find the dimensions of the rectangle, we can solve this equation along with the equation L * W = 96. However, there are multiple possible solutions, so we need additional information to determine the specific dimensions.
5. The size of a television is given by the diagonal of the screen. Let's assume the length of the television screen is L and the width is W. The diagonal of the screen is given as 40 inches.
Using the Pythagorean theorem, we have the equation L^2 + W^2 = 40^2.
Given that the area of the screen is 683 square inches, we have the equation L * W = 683.
To approximate the length and width of the television screen, we can solve these two equations simultaneously. However, it is important to note that the diagonal measurement alone does not provide enough information to determine the exact dimensions of the screen.