3. Sheila borrowed 30,000 from the bank @ 15% compounded yearly. What amount will she pay at the end of 2 years and 4 months to clear the loan? please tell me in picture
Sheila will need to pay 37,625 to clear the loan. In this case, the interest is compounded yearly, so n = 1. Therefore, Sheila will need to pay 37,625 to clear the loan. I hope this helps!
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Answer:
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Verified answer
[tex]A = (1 + \frac{R}{100} ) {}^{n} \\ \\ = 30,000 (1 + \frac{15}{100} ) {}^{2} \\ \\ = 30,000( \frac{115}{100} ) {}^{2} \\ \\ = \frac{39,67,50,000}{10,000} \\ \\ = 39,675[/tex]
[tex]Here \: T = 4 \: months \\ \\ = \frac{4}{12} \: years \\ \\ = \frac{1}{3} \: years[/tex]
[tex]SI = 39,675 \times \frac{15}{100} \times \frac{1}{4} \\ \\ = 39,675 \times \frac{15}{400} \\ \\ = \frac{5,95,125}{400} \\ \\ = 1,487.81[/tex]
[tex] = ₹ 39,675 +₹ \: 1,487.81 \\ \\ = ₹ \: 41,162.81 \: [/tex]