A ball is released from the top of a building of height h meters. It takes times Tseconds. Find the position of the ball after T/3 seconds
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Answer:
As we know that ball is dropped from height H A and takes T seconds to fall on the ground, so it's initial velocity (u) will be 0. H-H/9=9H-H/9=8H/9. HENCE AFTER T/3 SECONDS POSITION OF BALL WILL BE 8H/9 METRES FROM THE GROUND..