3. Negatively (-) charged balloon and the neutral soda cans.
a. What is the charge of the soda cans before the balloon approached it? (Picture A) A В.
b. What is the charge of the balloon as it approaches the soda cans? (Picture A)
C. What happened to the charges of the soda cans when the halloon is very close to the cans? (Picture B) Soda Can B
d. Did the balloon touch any of the cans?
e. What happened to the charge of the cans after they were separated? (Picture C) Picture B
f. What type of charging is being exhibited in the pictures? Soda Can A Soda Can B A B
Pakisagot po plsss
Rᴇᴡᴀʀᴅs ᴋᴜɴɢ ᴍᴀsᴀɢᴏᴛ:
ʟɪᴋᴇ ᴋᴏ ᴀɴsᴡᴇʀ ɴɪʏᴏ✔︎
ᴠᴏᴛᴇ ᴋᴏ ᴀɴsᴡᴇʀ ɴɪʏᴏ✔︎
ʙʀᴀɪɴʟɪᴇsᴛ ᴋᴏ ᴋᴀʏᴏ✔︎
ғᴏʟʟᴏᴡ ᴋᴏ ᴋᴀʏᴏ✔︎
ᴀᴛ ʟɪᴋᴇ ᴋᴏ ʟᴀʜᴀᴛ ɴɢ ᴀɴsᴡᴇʀ ɴɪʏᴏ✔︎
Need kona po pls sagot
Answers & Comments
Answer:
3.
a. Electrons do not move between the cans and the charged object. Whatever charge the balloon had before the induction process began is the charge it will have afterwards. The balloon is simply used to induce a movement of charge within the object which is being charged.
b. Two neutral conducting pop cans are touching each other. A negatively charged balloon is brought near one of the cans. The cans are separated while the balloon is nearby. After the balloon is removed the cans are charged.
c. The balloon was then filled with static electricity. When you held the negatively charged balloon close to the soda can, it attracted the positively charged protons in the aluminum.
d. no
e. When the cans are separated, they each have an excess of opposite charge. But when they are brought back together again with the balloon no longer nearby, there is an attraction between this excess of charge. This causes another movement of electrons back to the original neutral state.
f. soda can B
Answer:
3.a. What is the charge of the soda cans before the balloon approached it? (Picture A) A В.
Explanation:
I hope it's help