Answer:

Given, 4y + 1/3 + 2y + 1/2 + 3y/5 = 47/10

=> 6y + 3y/5 + 1/3 + 1/2 = 47/10

=> {(6*5 y + 3y)/5} + {(1*2 + 1*3/)6} = 47/10

=> {(30y + 3y)/5} + {(2 + 3/)6} = 47/10

=> 33y/5 + 5/6 = 47/10

=> 33y/5 = 47/10 -  5/6

=> 33y/5 = {(47*3 -  5*5)}/30

=> 33y/5 = {(141 -  25)}/30

=> 33y/5 = 116/30

=> 33y = (116/30)*5

=> 33y = (116*5)/30

=> 33y = 116/6

=> y = 116/(6*33)

=> y = 58/(3*33)

=> y = 58/99

So, the value of y is 58/99

Answer:

ans is 2

Explanation:

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