If (x^3+y^3/x^2)^-1 -(x^3+y^3/xy)^-1 +(x^3+y^3/xy^2)^-1 = 1/3 find the value of (x+y). Created by nidhijhanwar.

3 find the value of (x+y)...

June 2021 0 6 Report

If (x^3+y^3/x^2)^-1 -(x^3+y^3/xy)^-1 +(x^3+y^3/xy^2)^-1 = 1/3 find the value of (x+y)